12^2=x(x+10)

Solution for 12^2=x(x+10) equation:

12^2=x(x+10)

We move all terms to the left:

12^2-(x(x+10))=0

We add all the numbers together, and all the variables

-(x(x+10))+144=0


We calculate terms in parentheses: -(x(x+10)), so:

x(x+10)

We multiply parentheses

x^2+10x

Back to the equation:

-(x^2+10x)


We get rid of parentheses

-x^2-10x+144=0

We add all the numbers together, and all the variables

-1x^2-10x+144=0

a = -1; b = -10; c = +144;
Δ = b2-4ac
Δ = -102-4·(-1)·144
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*-1}=\frac{-16}{-2}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*-1}=\frac{36}{-2}
=-18
$